Two Sum
Problem
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example
1
2
3
Input: [2, 7, 11, 15], target = 9
Output: [0, 1]
Explanation: nums[0] + nums[1] = 2 + 7 = 9
My Answer
HashMap을 이용하자.nums를 순회하면서, target을 만들 수 있는 값을 찾자.target-nums[i]가nums[i]를 이용해서target을 만들 수 있는 값이고, 이것이HashMap에 있다면 정답.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
class Solution {
public int[] twoSum(int[] nums, int target) {
Map<Integer, Integer> map = new HashMap<>();
for (int i = 0; i < nums.length; i++) {
int complement = target - nums[i];
if (map.containsKey(complement)) {
return new int[] { map.get(complement), i };
}
map.put(nums[i], i);
}
return null;
}
}